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does define y as a function of x and use differentiation. y - ln y = x^2 + 1, dy/dx = 2xy/y - 1 x^2 + y^2 = 4, dy/dx = x/y e^xy + y = x - 1, dy/dx = e^-xy - y/e^-xy + x.
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Areas as double integrals (Section ) are of region on xy-plane below curve y = 4 − x2 and above y = integration order
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A cut for differentiation is using partial derivative (∂/∂x). you use partial derivative, you treat all variables, except one you are differentiating respect to, like a constant. For ∂/∂x [2xy + y^2] = 2y. In case, y is treated as a constant. is ∂/∂y [2xy
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require use of differentiation. differentiation is a special case of well-known rule for derivatives.
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Question: (3 points) all apply to differential equation dydx−sin2 (x)y=cos2 (x)y+xdydx−sin2 (x)y=cos2 (x)y+x A. ODE B. PDE C. first order D. second order E. order F. linear G. a candidate for integrating factors J. Question.
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A cut for differentiation is using partial derivative (∂/∂x). you use partial derivative, you treat all variables, except one you are differentiating respect to, like a constant. For ∂/∂x [2xy + y^2] = 2y. In case, y is treated as a constant. is ∂/∂y [2xy.
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dy dx +y = x. IF is e∫dx = ex so. ex dy dx +exy = xex. or. d dx (exy) = xex. so.
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/2/16 page 83 Exact Differential Equations 83 given differential equation is exact
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